$\frac{\left(-2\right)\left(4\right)\left(-6\right)}{-3}$
$6b-8b-3a-6b$
$\left(-4x^{-2}j^5c\right)^3$
$25a^3b-36ab^3$
$-6\:-\:\left(-7\right)\:+\:\left(-17\right)$
$y^2-y-72$
$\left(4^3\right)^7$
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