$\lim_{x\to\infty}\left(\frac{2x^3+3x+1}{5x^4-8x^2-3}\right)$
$x^2-4x+6$
$\left(2x-3\right)\left(2x-3\right)$
$2\left(-\sin\left(2x\right)+\cos\left(2x\right)\right)$
$3x^2+7x^2-6+7x-8-x+5x^2$
$\frac{2x}{x+3}\le\:1$
$4b\:+\:5b^2$
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