$3+99+99$
$\int\left(1+x\right)^2\sqrt{x}\:dx$
$\int_0^{\frac{2\pi}{3}}\left(\sqrt{16-16sin^2\left(x\right)}\right)dx$
$4x+\left(12\right)=48$
$6x^3+3x^5-3x-6x^6$
$\int\left(6xe^{-2x}\right)dx$
$\left(64x^4-81\right)\left(4x-3.\right)$
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