$\frac{x+2ax+a^2}{mx+ma}$
$6+-3\cdot\left(4-7\right)$
$3x+2y=24$
$\sqrt{\left(\frac{-2kq}{\sqrt{2a}}\right)^2+\left(\frac{-2kq}{\sqrt{2a}}\right)^2}$
$10+2x-3x$
$=\left(+7\right)\left(+5\right)\left(-3\right)$
$2y\left(\frac{29}{130}9^y\right)$
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