$-\frac{3}{5}x=9$

$\int2t^4dt$

$\cos^2\left(3x\right)-\sin^2\left(3x\right)=-1$

$\cot\left(x\right)=\frac{17.22}{6.59}\cdot sin\left(0.24\right)$

$\left(-512\right)\cdot\left(27\right)$

$\left(-7x^3+6x^2-5\right)+\left(9x^3-6x-2\right)$

$\lim_{x\to\infty}\left(\frac{2}{x}\:+\:5\right)$