$\int\left(\frac{3\sin\left(x\right)}{2}+\frac{\cos\left(x\right)}{3}\right)dx$
$3-x\:\frac{dy}{dx}=8$
$\left(3x^2-2x+5\right)-00$
$-10-4+33+9-233$
$2+5b^2+8b^2+1$
$3\cdot\sin\left(y\right)=x+6\cdot\sin\left(y\right)$
$x\:2\:+9x+6x+54-x^2+3x+2x+6x\:2\:+3x+2x+6$
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