$\frac{\left(4x^4-1\right)^2}{16x^4}+1$

$\left(7a^{2}+2b^{3}\right)\left(7a^{2}-2b^{5}\right)$

$\int_{-\infty\:}^{6.44}0,19947\cdot e^{-\frac{x^2}{8}}dx$

$\lim_{x\to3}\left(4-4x\right)$

$300-104$

$\lim_{x\to0}\left(\cos\left(2x\right)\right)^{\frac{1}{x^2}}$

$\left(2x+5\right)\cdot\left(2x-5\right)\le11$