$3^3+6^2+2^4$
$\left(14\right)\left(21\right)\left(32\right)$
$y'=x\left(1-y\right)^{\left(0.5\right)}$
$\int_0^{\sqrt{2}}\left(3xe^{x^2+1}\right)dx$
$\mid3-2x\mid\mid\:x+4\mid$
$\int\frac{8x^3}{\sqrt{-2x^4-8}}dx$
$3x+4\ge2\left(x-7\right)$
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