$2x^4-x^3-3+7\:\:$
$-\:16.4\:+\:\left(-4.6\right)$
$\lim_{x\to0}\frac{3x^{\:3}-4}{x^2}$
$\left(40\right)\left(-2\right)\left(29\right)\left(-10\right)$
$-2\left(5y-3a\right)^2$
$\left(6f^6-3\right)\left(6f^6+6\right)$
$\left(\frac{1}{2}x+5\right)^2$
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