∫((x2+2x−4)2(x+1))dx\int\left(\left(x^2+2x-4\right)^2\left(x+1\right)\right)dx∫((x2+2x−4)2(x+1))dx
tan2x−8tanx+16\tan^2x-8\tan x+16tan2x−8tanx+16
8−3(n−4)=5(3n+2)−88-3\left(n-4\right)=5\left(3n+2\right)-88−3(n−4)=5(3n+2)−8
limx→2(5x+6)\lim_{x\to2}\left(5x+6\right)x→2lim(5x+6)
(9mx+3ny)2\left(9m^x+3n^y\right)^2(9mx+3ny)2
∫x−arctan 2x1+4x2dx\int\frac{x-\sqrt{arctan\:2x}}{1+4x^2}dx∫1+4x2x−arctan2xdx
[28−( − 10)]−7\left[28-\left(\:-\:10\right)\right]-7[28−(−10)]−7
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