$\frac{1}{\cos\left(\frac{x}{2}\right)^2}$
$-4\cdot\left(-3\right)+\left(-3\right)\cdot\left(-2\right)-12$
$\int-40dx$
$a^3-3a^2-9a+27$
$\sqrt{64a^5b^6}$
$\lim_{x\to\pi}\left(\frac{1+\cos\left(x\right)}{1-\cos\:\left(x\right)}\right)$
$\frac{2a^5b^9}{8a^5b}$
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