$2abc-7b^2$
$\sqrt{x^3-2}y'\:=\:x^2$
$\left(5x-4\right)^2=64$
$\int_0^{+\infty}\left(\frac{x}{x^2+3}\right)dx$
$\frac{d}{dx}\left(\left(xy+y^2\right)^{0.5}=x\right)$
$\int\frac{\left(x^5\right)}{\left(ln\left(x^3+5\right)\right)}dx$
$y'+3xy^3=0$
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