2lnx−ln(x+2)=02\ln x-\ln\left(x+2\right)=02lnx−ln(x+2)=0
∫(4x2+2)ln(x)dx\int\left(4x^2+2\right)\ln\left(x\right)dx∫(4x2+2)ln(x)dx
∫(2x+5x2+4x−12)dx\int\left(\frac{2x+5}{x^2+4x-12}\right)dx∫(x2+4x−122x+5)dx
∫445+4x−x2dx\int_4^4\sqrt{5+4x-x^2}dx∫445+4x−x2dx
2⋅(15−3)−(11−(7−3))2\cdot\left(15-3\right)-\left(11-\left(7-3\right)\right)2⋅(15−3)−(11−(7−3))
(ex)2\left(ex\right)^2(ex)2
x2(dydx)−yx=0x^2\left(\frac{dy}{dx}\right)-y\sqrt{x}=0x2(dxdy)−yx=0
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