$\frac{\tan^2\left(a\right)+1}{\tan\left(a\right)+1}=\sec^2\left(a\right)-\tan\left(a\right)$
$\int\log\left(xe^{7x}\right)dx$
$2x-10<6x+2$
$15x+10y$
$64.50+23.25$
$4.56\cdot3.45$
$\left(b+13\right)\left(b-13\right)$
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