$\frac{x^5+x+4}{x^2+3x+2}$
$\left(\left(8x^2\right)+1\right)\left(16\right)$
$\frac{36x^4-109x^2+25}{3x-5}$
$-18-\left(-55\right)$
$x+1.x+2+x+2.x+3-2+x+5.x-2-x$
$-5r\:\:+\:-2r$
$9\tan\:x\sin\:x=10\sin\:x$
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