$\lim_{x\to2}\left(\frac{x^2+2x-8}{\left(x+1\right)-\sqrt{x^2+5}}\right)$
$2v\left(v-2\right)=0$
$4x^3+2x^2-3x+2-5x^3+2x^2-4x-2$
$4\cdot 23^2\cdot 1$
$\frac{3^9}{\left(-3^{\:6}\right)}$
$\frac{d}{dx}x=\frac{1}{x}$
$\left(-15x^4y^3\right)\left(16\:a^2x^3y\right)$
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