$2x+7\ge5$
$\int\left(2x\left(x^2+12\right)^9\right)dx$
$\lim_{x\to\infty}\left(\frac{e^x-x-1}{cos\left(2x\right)-1}\right)$
$\int\:\left(3x^4+10\right)^3\left(12x^3\right)dx$
$mx+1-5mx+1$
$15\left(2x^2-5x+7\right)-8\left(\left(x-2\right)\left(x-4\right)\right)$
$-7x+x^2=18$
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