Simplifying
$\int\frac{5}{9-x^2}dx$
$\left(e^{2t}\right)^2$
$x^3-x^9$
$\frac{\left(7^a\right)^b}{7^b}$
$-\left|-35\right|+15$
$0-34z^4$
$3.14d=c$
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