$$x+3=2x+1$$

$$\frac{16x^4-81y^8}{2x-4y^2}$$

$$\int_{18}^{\infty}\left(0.06\cdot e^{-0.06}\right)dx$$

$$\frac{t}{\frac{c}{3}}$$

$$-8x<48$$

$$\left|3-\left(10\right)\right|$$

$$\frac{d}{dx}y=\left(x-\frac{1}{x^2}\right)^5$$