$\int x^3\left(x^4-3\right)^8dx$

$-\left(+8\right)-\left(-6+6-2\right)$

$\int\frac{1}{2\sqrt{x^2-1}}dx$

$\left(2a+b-3c+4\right)^2$

$2\left(\frac{2}{5}xy\right)\left(\frac{3}{4}x^2y^2\right)$

$4-8\ln\left(x\right)=9$

$\cos\left(x\right)\sin\left(3x\right)-\sin\left(x\right)\cos\left(3x\right)=1$