$3\tan^2x-1=\sec^2x$

$4\left(5x-10\right)=20\left(x-10\right)$

$\frac { ( x ^ { 2 } ) ^ { 3 } ( x ^ { 3 } ) ^ { 2 } } { ( x ^ { 3 } ) ^ { 4 } }$

$40+30-10$

$1-121x^4$

$\frac{dy}{dx}=\frac{\left(1+e^{-y}\right)\cdot sin\left(x\right)}{1+cos\left(x\right)}$

$\int\arccot\left(10y\right)dy$