$x^{10}-x^9+x^8+3x^6-4$
$1+\frac{7}{x+6}=\frac{7}{x^2+13x+42}$
$\int_{-1}^5\left(\frac{x^2+1}{x^2+4}\right)dx$
$\frac{1-tan^2x}{1-cot^2x}$
$x^{2}+4x+4<0$
$csca\cdot seca=cota+tana$
$3x+5x^2=-1$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!