$$\lim_{x\to3.8}\left(\frac{x^2-16}{x+4}\right)$$

$$-25x^4y^2-121$$

$$m\left(-3\right)=-5\left(-3\right)-5$$

$$\frac{d}{dx}\left(\frac{x^5\left(x-9\right)^3}{\left(x^2+2\right)^3}\right)$$

$$-325+10$$

$$x^2-6x+8\le0$$

$$\frac{2}{3}\left(x+2y\right)=\left(\frac{2}{3}\left(x+1\right)\right)\left(\frac{1}{3}+\left(\frac{3}{4}y\right)\right)$$