$\frac{dy}{dx}=\frac{x^3}{q^8}$
$\lim_{x\to0}\left(\frac{\cos\left(4x\right)-1}{x\tan\left(3x\right)}\right)$
$a^{10}-2a^3+1$
$\left(x+15\right)\left(x-9\right)$
$\sin^2\left(2\pi x\right)-1=0$
$k^2+26k+169k$
$33.8-\left(-2.746\right)$
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