$4x<-24$
$x^2\frac{4}{3}x+\frac{4}{9}$
$\lim_{x\to\infty}\left(\frac{3x-5}{3x+3}\right)^{2x+1}$
$-\left(x+3\right)\left(x-5\right)$
$\left(3x^3+\sqrt{2}\right)^2$
$5m^4\:\:6m^2$
$-1992-\left[-2017\right]$
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