$\int_{-\pi}^{\pi}\left(\sin\left(\frac{\left(4x+9\pi\right)}{18}+3\pi\right)\right)dx$
$3x-19<x-5$
$-\left(3-a\right)^5$
$\lim_{x\to6}\left(\frac{e^{8x}-1}{sin\left(x\right)}\right)$
$x^2-8x+41=0$
$2x\:-\:10\:\le3.\left(x-1\right)$
$5+x=1$
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