$\left(7ax\right)^2$
$-14+2\left(-9+6\cdot3\right)$
$\frac{-8}{x^2-3x}$
$\int\left(-3x\left(3x^2-2\right)^4\right)dx$
$\frac{-2}{5}a^2\frac{7}{5}a^4\frac{-9}{5}a^4$
$\frac{\left(\sec x-1\right)}{\sec x+1}$
$p\left(x\right)=abx^2-acx$
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