$\left(2^d+7^a\right)^2$
$\lim_{x\to2}\left(\frac{\sqrt{4x-1}-3}{x-2}\right)$
$25x^212x+9$
$11+3x>11$
$\frac{d}{dx}v=\frac{1}{3}\pi d^2x$
$\frac{x}{3}+17=12$
$\lim_{x\to\infty}\left(4-9x^7-8x^8\right)$
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