$\left(1+\tan\left(x\right)\right)\left(1+\cot\left(-x\right)\right)=\tan\left(x\right)-\cot\left(x\right)$
$m-14=0$
$49a^2b^4c^6-121m^6n^{10}$
$\int\frac{1}{\left(2x+1\right)\left(x+3\right)}dx$
$\int\:t\:^2\:e^t\:dx$
$-4x+7>x+12$
$\left(4d+1\right)^2$
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