$\left(-3x\frac{1}{3}\right)^2\left(4x\frac{1}{4}\right)^4$
$x^2-4x>0$
$\int\frac{x^2-1}{x-2\left(x^2+1\right)}dx$
$\lim_{x\to9}\left(-\frac{\left|x-2\right|}{x-2}3\right)$
$x\left(x^3-3x^2-12\right)-16$
$\int\frac{3xe^{8x}}{2}dx$
$x^2y^'-2y=0$
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