$\frac{4x}{16x^3-4x}$
$-3x+4y+5x+7+3y$
$\frac{2}{x-8}=\frac{x-2}{x-1}$
$\left(4a^2-1\right)^2$
$5a-7a+3a$
$1-6y+12y-8y^{3}$
$2x^2\sqrt{7y}$
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