$2x+4=3x-10$
$\left(3x-7\right)\left(x+2\right)_{-2x^2}\le\left(x+2\right)^2$
$\frac{1\cdot10^8\cdot\infty^2}{4\cdot10^8\cdot\infty^2+1}$
$\left(5ab^2-2\right)\left(5ab^2+2\right)$
$\frac{3x^4+19x^3+22-6x+4}{x-2}$
$8-3\left(2+9\right)$
$\left(2m\:+\:5x^2\right)^3$
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