$\frac{d}{dx}xy=x+y$
$\left(\sqrt{\frac{4x^2}{2^4}}\right)\left(\sqrt{\frac{9x^4}{3^6}}\right)$
$4t-t^2+1$
$20\cdot3+5^2-4\cdot4+3^2$
$5u^3+8u^2$
$\sqrt[3]{8-1\cdot8^{3^{-1}}+16^{2^{-2}}}$
$6\cdot\left(2x+3y\right)^2$
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