$\frac{5.5}{8.25}=\frac{x}{22.5}$
$\frac{d}{dx}\left(x^x\right)\left(3x-3\right)^3\cdot\left(4x^2+4\right)^4$
$3\lim_{x\to8}\left(2.71828182846^8\right)$
$-7x^0y$
$\frac{dy}{dx}=\:-432x^5+90x^4+528x^3-99x^2$
$18m\:-\:9n$
$8x^2y^3\cdot6x^2$
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