$\frac{dy}{dx}=\frac{2y+4x}{2x}$

$\int\left(\frac{2q\ln\left(q^2+1\right)}{\left(q^2+1\right)}\right)dq$

$\tan^2\left(x\right)\sec^2\left(x\right)-\tan^2\left(x\right)$

$6x\left(8x+1\right)-3\left(4x+1\right)=6x+3$

$x\:in\:x$

$\int\left(e^{\left(2y-3\right)}\right)dx$

$\int\frac{2x-7}{x^2+2x-4}dx$