$\left(y^4-36\right)$
$\lim_{x\to\infty}\left(-6x^3-x^2\right)$
$\frac{4x\left(2x^3-3x^{-1}\right)}{x^2+1}$
$12x^2+20y^2+40y-37=0$
$-1<x$
$4y+5>6y+7$
$\lim_{t\to\infty}\left(\frac{2e^{2t}-3}{7+5e^{4t}}\right)$
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