$\left(6a^3-9b^2\right)\left(6a^3+9b^2\right)$
$3\left(x-4\right)+7x+5$
$\frac{2x}{x^2-25}-\frac{2}{x+5}$
$\frac{\sqrt[3]{27x^6y^2z}}{3},\:\sqrt[3]{\frac{x^9y^2z}{125}},\:x^2\sqrt[3]{64y^2z}$
$\frac{x+1}{x^2-3x}$
$-x+3<0$
$\frac{x^3-y^3}{x-4}$
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