f(x)=(5x3−x2+1)(3x2−2x−1)f\left(x\right)=\left(5x^3-x^2+1\right)\left(3x^2-2x-1\right)f(x)=(5x3−x2+1)(3x2−2x−1)
∫1∞ 1xp+1dx\int_1^{\infty\:}\frac{1}{x^{p+1}}dx∫1∞xp+11dx
(2y3)(9y4)\left(2y^3\right)\left(9y^4\right)(2y3)(9y4)
(8w−20)⋅(2q+3)\left(8w-20\right)\cdot\left(2q+3\right)(8w−20)⋅(2q+3)
2,53 + 57,65 − 672,53\:+\:57,65\:-\:672,53+57,65−67
−3n − 7+(−6n)+1-3n\:-\:7+\left(-6n\right)+1−3n−7+(−6n)+1
(63x5−36x4+72x3−45x+27)(x+2)\left(63x^5-36x^4+72x^3-45x+27\right)\left(x+2\right)(63x5−36x4+72x3−45x+27)(x+2)
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