∫5sen4(x)dx\int5sen^4\left(x\right)dx∫5sen4(x)dx
2x(x+1)2\:\frac{2x}{\left(x+1\right)^2}(x+1)22x
∫5x−7dx\int5x^{-7}dx∫5x−7dx
limx→∞4x2+25x3+6\lim_{x\to\infty}\frac{4x^2+2}{5x^3+6}x→∞lim5x3+64x2+2
dydt=1+y2\frac{dy}{dt}=1+y^2dtdy=1+y2
∫x3+3x(x2+1)dx\int\frac{x^3+3x}{\left(x^2+1\right)}dx∫(x2+1)x3+3xdx
2x−1−3 x−2=0\frac{2}{x-1}-\frac{3}{\:x-2}=0x−12−x−23=0
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