$\left(2s^2-3t^3\right)^3$
$\frac{y}{y+xy}$
$x^2-4<4-2x$
$\frac{8x^3y^2}{2x^3y}$
$\left(3x^3-2x^2+2x+7\right)x\left(2x^2+x+1\right)$
$-3x\:+\:5\:<\:-5x\:+\:2$
$\:y'=\:xe^{x^2+4y}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!