$6y+8>11$
$5a^2b^3\left(2ab-3a-1\right)$
$\left(-10\right)-\left(-8\right)$
$\left(5x^2+6x^3+2x\right)-\left(3x-2x^3-7x^2\right)$
$3a+\:b^2+\:2a^2+\:b-7a+\:b^2$
$\int\frac{\sin^2\left(x+3\right)}{\tan\left(x+3\right)}dx$
$\int\frac{1}{x^2-4x-8}dx$
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