$\left(2a-bc^2\right)^3$
$\frac{2a^2-a-15}{2a+5}$
$2x^2+4xy-8$
$1\cdot\left(x^{5}+10\right)\left(x^{5}-10\right)$
$6\left(-3x+8\right)=-6\left(8x-8\right)$
$\left(2x+3\right)\left(x+5\right)$
$x^4-8x^2-240$
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