$tan2x+1=0$
$\left(5x^2-3y^3\right)\left(5x^2+3y^3\right)$
$\lim_{x\to0}\left(5x+1\right)$
$5c+7c-4c$
$sin\left(90^{\circ\:}+\theta\:\right)=cos\theta\:$
$\frac{7\left(x-3\right)}{x-4}+\frac{2}{x}=-\frac{2}{x\left(x-4\right)}$
$2+5x+3+4x$
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