$x=2,y=3,z=-2$
$\left(-51\right)\cdot\left(-21\right)$
$-3x+4<10$
$\ln\left(x+5\right)=\ln\left(x-1\right)$
$\frac{dy}{dx}=-\frac{x^3+3y^2x}{y^3+3x^2y}$
$-0.24\left(-3.25+5.65\right)$
$1+secx\left(1-secx\right)$
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