$4\cdot\frac{1}{2}\sqrt[3]{24\cdot9}$
$4+8>16$
$5^x=n$
$cos\left(2arctan\left(-2\right)\right)$
$\frac{dy}{dx}=\:3ye^x$
$-4\left(x-3\right)=-x$
$\lim_{x\to-2}\left(\frac{x^2-4}{2x+4}\right)$
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