$\frac{24\sqrt{2}}{2}$
$\left(4d-3\right)\left(4d+9\right)$
$\lim_{x\to0}\left(\frac{\left(x+2\right)^3-8}{2x}\right)$
$\left(x^2+16\right)\left(x-3\right)\left(x+4\right)$
$\frac{x^5-x^4+x^2-2}{x^2+1}8$
$\lim_{h\to0}\left(2h^3-5h^2+1\right)$
$x^3+4x^2-16x-64$
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