$\frac{\left(x-1\right)^2}{4}=\frac{x+5}{6}+x$
$\int\left(1-x\right)\left(e^{20x-10x^2}\right)dx$
$\int x^{\frac{5}{4}}dx$
$z+7.z+8$
$x^4y+x^2+6yx3$
$5.30\cdot10$
$7^4\cdot7^{-4}$
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