∫0π23xcos2x3dx\int_0^{\sqrt[3]{\pi^2}}\sqrt{x}cos^2\sqrt{x^3}dx∫03π2xcos2x3dx
4x(−11)4x\left(-11\right)4x(−11)
(x2−3y)(x4+3x2y+9y2)\left(x^2-3y\right)\left(x^4+3x^2y+9y^2\right)(x2−3y)(x4+3x2y+9y2)
a(x)=x5−1x−1a\left(x\right)=\frac{x^5-1}{x-1}a(x)=x−1x5−1
ddx(xx2+6)\frac{d}{dx}\left(x\sqrt{x^2+6}\right)dxd(xx2+6)
5w2−3w5w^2-3w5w2−3w
(16−3=(x+7))\left(\frac{1}{6}^{-3}=\left(x+7\right)\right)(61−3=(x+7))
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