3⋅33\sqrt{3}\cdot\frac{\sqrt{3}}{3}3⋅33
3cot2x+1=0\sqrt{3}\cot2x+1=03cot2x+1=0
cos4t−sin4t=1−2sin2tcos^4t-sin^4t=1-2sin^2tcos4t−sin4t=1−2sin2t
2(3+3)2\left(3+3\right)2(3+3)
8x3−4x\frac{8}{x^3-4x}x3−4x8
cosbcotb⋅cot2bcos2b\frac{cosb}{cotb}\cdot\frac{cot^2b}{cos^2b}cotbcosb⋅cos2bcot2b
(4x−7)3\left(4x-7\right)^3(4x−7)3
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