$6^{-4}\cdot6^4$
$\frac{x^4-2x^3-3x^2+4}{x-3}$
$\frac{d}{dx}\sqrt{2x^2-4}$
$\frac{dx}{dt}=\frac{t}{2x}$
$-4n+n^4-6+7n^2-2n^2$
$30>6\cdot x$
$4^3\:\cdot16$
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